What will be the output of the following code: let s_prim = 'foo'; let s_obj = new String(s_prim); console.log(typeof s_prim);?

What will be the output of the following code: let s_prim = 'foo'; let s_obj = new String(s_prim); console.log(typeof s_prim);?

• A. String
• B. Object
• C. Boolean
• D. Array

Answer: (A)

The output of the code `let s_prim = 'foo'; let s_obj = new String(s_prim); console.log(typeof s_prim);` will indeed show that the type of `s_prim` is a String. In JavaScript, when you declare a variable using a string literal like `let s_prim = 'foo';`, the variable `s_prim` is assigned a primitive string value. The `typeof` operator, when applied to a primitive string, returns the string "string". The distinction here is that `s_obj` is created using the `String` constructor (`new String(s_prim)`), which creates a String object, not a primitive. However, the type of the original variable `s_prim` remains unaffected, and it retains its type as a primitive string. Therefore, when the `console.log(typeof s_prim);` statement is executed, it correctly outputs "string", verifying that `s_prim` is indeed of the type String.

The output of the code let s_prim = 'foo'; let s_obj = new String(s_prim); console.log(typeof s_prim); will indeed show that the type of s_prim is a String.

In JavaScript, when you declare a variable using a string literal like let s_prim = 'foo';, the variable s_prim is assigned a primitive string value. The typeof operator, when applied to a primitive string, returns the string "string".

The distinction here is that s_obj is created using the String constructor (new String(s_prim)), which creates a String object, not a primitive. However, the type of the original variable s_prim remains unaffected, and it retains its type as a primitive string.

Therefore, when the console.log(typeof s_prim); statement is executed, it correctly outputs "string", verifying that s_prim is indeed of the type String.